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A theorem on nilpotency in near-rings
Published online by Cambridge University Press: 20 January 2009
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Throughout this paper a near-ring N will satisfy the distributive law α(β + γ)=αβ + αγ for all α, β and γ in N. We shall also assume that 0α = 0 for all α in N
We prove the following theorem.
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- Copyright © Edinburgh Mathematical Society 1978