Geometrical Proof of tan A + tan B + tan C = tan A tan B tan C

Colin Kesson

doi:10.1017/S1757748900001602

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Geometrical Proof of tan A + tan B + tan C = tan A tan B tan C

Published online by Cambridge University Press: 31 October 2008

Colin Kesson

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Let ABC be the Δ, AD ⊥ to BC produced to meet circumcircle in K, BL a diameter of circumcircle, LM ⊥ to AK. Let BK, KG, CL and LA be joined.

Type: Research Article
Information: Edinburgh Mathematical Notes , Volume 20 , April 1916 , pp. 231 - 232

DOI: https://doi.org/10.1017/S1757748900001602 [Opens in a new window]
Copyright: Copyright © Edinburgh Mathematical Society 1916

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Geometrical Proof of tan A + tan B + tan C = tan A tan B tan C

Volume 20
Colin Kesson
DOI: https://doi.org/10.1017/S1757748900001602

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Geometrical Proof of tan A + tan B + tan C = tan A tan B tan C

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