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Perfect McLain groups are superperfect
Published online by Cambridge University Press: 17 April 2009
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It is shown that if a McLain group is perfect, then it is super-perfect. The proof involves demonstrating that any dense linearly ordered set has the apparently stronger property of being superdense.
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- Copyright © Australian Mathematical Society 1984
References
[1]Berrick, A.J., An approach to algebraic k-theory (Pitman Research Notes in Mathematics, 56. Pitman, London, 1982).Google Scholar
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[4]Robinson, Derek J.S., Finiteness conditions and generalized soluble groups, Part II (Ergebnisse der Mathematik und ihrer Grenzgebiete, 63. Springer-Verlag, Berlin, Heidelberg, New York, 1972).CrossRefGoogle Scholar
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