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A quadratic recurrence of Faltung type - Corrigenda
Published online by Cambridge University Press: 24 October 2008
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E. M. Wright. ‘A quadratic recurrence of Faltung type.’
Middle of p. 197. The value of x( − ⅓) should be
x (− ⅓) = 0·351298985… = ei−1 × 0·95492965…
The error was mine and not Dr Ponting's.
- Type
- Corrigenda
- Information
- Mathematical Proceedings of the Cambridge Philosophical Society , Volume 92 , Issue 2 , September 1982 , pp. 379
- Copyright
- Copyright © Cambridge Philosophical Society 1982
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