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Elementary equivalence and the commutator subgroup
Published online by Cambridge University Press: 18 May 2009
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If G and H are elementarily equivalent groups (that is, no elementary statement of group theory distinguishes between G and H) then the definable subgroups of G are elementarily equivalent to the corresponding ones of H. But G′ of G, consisting of all products of commutators [a, b] = a−1b−1ab of elements a and b of G, may not be definable. Must G′ and H′ be elementarily equivalent?
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- Copyright © Glasgow Mathematical Journal Trust 1982
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